model 1 profit x after discount y Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (c)

If the C.P. of grinder be x, then

${x × 108}/100 = {3600 × 90}/100$ = 3240

$x = {3240 × 100}/108$ = Rs.3000

Using Rule 6,

M.P. = Rs.3600, D = 10%,

r = 8%, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$3600/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${3600 × 90}/108$

= ${3600 × 10}/12$ = Rs.3000

Answer: (a)

S.P. of that article

= 800 × $90/100$ = Rs.720

He still makes 20% profit

C.P. of the article

= 720 $×100/120$ = Rs.600

Here, r = 20%, D = 10%, M.P. = Rs.800, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$800/\text"CP" = {100 + 20}/{100 - 10}$

C.P. = ${800 × 90}/120$

C.P. = Rs.600

Answer: (b)

Let C.P. of article = Rs.100

Marked price = x

Single equivalent discount

= $(20 + {25/4} - {20 × 25}/400)$% = 25%

$x × 75/100$ = 120

$x = {120 × 100}/75$ = Rs.160

160 - 100 = 60%

Answer: (c)

Let C.P. of article be x

${x × 104.5}/100 = {275 × 95}/100$

x × 104.5 = 275 × 95

$x = {275 × 95}/{104.5}$ = Rs.250

Using Rule 6,

M.P. = Rs.275, D = 5%,

r = 4.5%, C.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$275/\text"C.P." = {100 + 4.5}/{100 - 5}$

C.P. = ${275 × 95}/{104.5}$

C.P. = Rs.250

Answer: (a)

Let the C.P. of article be Rs.100 and its marked price be x.

$x × 84/100 = 105$

$x = {105 × 100}/84 = 125$

Required percentage = 25%

Using Rule 6,

Here, r = 5% D = 16%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

= ${100 + 5}/{100 - 16} = 105/84$

Required Percentage

= ${105 - 84}/84 × 100$ = 25%